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0=4x^2+2x-30
We move all terms to the left:
0-(4x^2+2x-30)=0
We add all the numbers together, and all the variables
-(4x^2+2x-30)=0
We get rid of parentheses
-4x^2-2x+30=0
a = -4; b = -2; c = +30;
Δ = b2-4ac
Δ = -22-4·(-4)·30
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-22}{2*-4}=\frac{-20}{-8} =2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+22}{2*-4}=\frac{24}{-8} =-3 $
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